Base | Representation |
---|---|
bin | 11101100101010001001100… |
… | …001110111110100011000011 |
3 | 122001122212021022022211222202 |
4 | 131211101030032332203003 |
5 | 114023112332122400214 |
6 | 1140413052123223415 |
7 | 36255510006626606 |
oct | 3545211416764303 |
9 | 561585238284882 |
10 | 130104428325059 |
11 | 38500a83a79501 |
12 | 12713139977b6b |
13 | 5779a446643c6 |
14 | 241b1333cc33d |
15 | 10094ac4646de |
hex | 76544c3be8c3 |
130104428325059 has 2 divisors, whose sum is σ = 130104428325060. Its totient is φ = 130104428325058.
The previous prime is 130104428325007. The next prime is 130104428325061. The reversal of 130104428325059 is 950523824401031.
It is a strong prime.
It is an emirp because it is prime and its reverse (950523824401031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130104428325059 - 232 = 130100133357763 is a prime.
Together with 130104428325061, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (130104428325559) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65052214162529 + 65052214162530.
It is an arithmetic number, because the mean of its divisors is an integer number (65052214162530).
Almost surely, 2130104428325059 is an apocalyptic number.
130104428325059 is a deficient number, since it is larger than the sum of its proper divisors (1).
130104428325059 is an equidigital number, since it uses as much as digits as its factorization.
130104428325059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1036800, while the sum is 47.
The spelling of 130104428325059 in words is "one hundred thirty trillion, one hundred four billion, four hundred twenty-eight million, three hundred twenty-five thousand, fifty-nine".
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