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130104428325059 is a prime number
BaseRepresentation
bin11101100101010001001100…
…001110111110100011000011
3122001122212021022022211222202
4131211101030032332203003
5114023112332122400214
61140413052123223415
736255510006626606
oct3545211416764303
9561585238284882
10130104428325059
1138500a83a79501
1212713139977b6b
135779a446643c6
14241b1333cc33d
1510094ac4646de
hex76544c3be8c3

130104428325059 has 2 divisors, whose sum is σ = 130104428325060. Its totient is φ = 130104428325058.

The previous prime is 130104428325007. The next prime is 130104428325061. The reversal of 130104428325059 is 950523824401031.

It is a strong prime.

It is an emirp because it is prime and its reverse (950523824401031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130104428325059 - 232 = 130100133357763 is a prime.

Together with 130104428325061, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130104428325559) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65052214162529 + 65052214162530.

It is an arithmetic number, because the mean of its divisors is an integer number (65052214162530).

Almost surely, 2130104428325059 is an apocalyptic number.

130104428325059 is a deficient number, since it is larger than the sum of its proper divisors (1).

130104428325059 is an equidigital number, since it uses as much as digits as its factorization.

130104428325059 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1036800, while the sum is 47.

The spelling of 130104428325059 in words is "one hundred thirty trillion, one hundred four billion, four hundred twenty-eight million, three hundred twenty-five thousand, fifty-nine".