Base | Representation |
---|---|
bin | 1011110101010100000101… |
… | …0010100010111001011011 |
3 | 1201001210111200200010110212 |
4 | 2331111001102202321123 |
5 | 3201131102114221110 |
6 | 43400544220001335 |
7 | 2511660406343624 |
oct | 275250122427133 |
9 | 51053450603425 |
10 | 13010551320155 |
11 | 41668200437a4 |
12 | 156164739024b |
13 | 734b74958c1c |
14 | 32d9dd49ca4b |
15 | 17867ab48e05 |
hex | bd5414a2e5b |
13010551320155 has 8 divisors (see below), whose sum is σ = 16151029225200. Its totient is φ = 10049529295456.
The previous prime is 13010551320139. The next prime is 13010551320157. The reversal of 13010551320155 is 55102315501031.
13010551320155 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13010551320155 - 24 = 13010551320139 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13010551320157) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44863969925 + ... + 44863970214.
It is an arithmetic number, because the mean of its divisors is an integer number (2018878653150).
Almost surely, 213010551320155 is an apocalyptic number.
13010551320155 is a deficient number, since it is larger than the sum of its proper divisors (3140477905045).
13010551320155 is an equidigital number, since it uses as much as digits as its factorization.
13010551320155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89727940173.
The product of its (nonzero) digits is 11250, while the sum is 32.
Adding to 13010551320155 its reverse (55102315501031), we get a palindrome (68112866821186).
The spelling of 13010551320155 in words is "thirteen trillion, ten billion, five hundred fifty-one million, three hundred twenty thousand, one hundred fifty-five".
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