Base | Representation |
---|---|
bin | 111100100101100101… |
… | …1000110011110110100 |
3 | 110102211121100000022220 |
4 | 1321023023012132310 |
5 | 4112431204021322 |
6 | 135434413322340 |
7 | 12254152424040 |
oct | 1711313063664 |
9 | 412747300286 |
10 | 130110220212 |
11 | 501a7911215 |
12 | 212717963b0 |
13 | c3669861ab |
14 | 6423d9b020 |
15 | 35b788655c |
hex | 1e4b2c67b4 |
130110220212 has 48 divisors (see below), whose sum is σ = 347327178240. Its totient is φ = 37135071072.
The previous prime is 130110220183. The next prime is 130110220217. The reversal of 130110220212 is 212022011031.
It is a junction number, because it is equal to n+sod(n) for n = 130110220191 and 130110220200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130110220217) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 738262 + ... + 897357.
It is an arithmetic number, because the mean of its divisors is an integer number (7235982880).
Almost surely, 2130110220212 is an apocalyptic number.
130110220212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
130110220212 is an abundant number, since it is smaller than the sum of its proper divisors (217216958028).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130110220212 is a wasteful number, since it uses less digits than its factorization.
130110220212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1636580 (or 1636578 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 130110220212 its reverse (212022011031), we get a palindrome (342132231243).
The spelling of 130110220212 in words is "one hundred thirty billion, one hundred ten million, two hundred twenty thousand, two hundred twelve".
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