Search a number
-
+
13011032551135 = 5149110915747947
BaseRepresentation
bin1011110101010101110111…
…1110010010111011011111
31201001211202020012012021111
42331111131332102323133
53201133043313114020
643401104050242451
72512005341626453
oct275253576227337
951054666165244
1013011032551135
114166a47750753
121561760586427
13734c2056bc98
1432da4736a663
151786a8005d5a
hexbd55df92edf

13011032551135 has 16 divisors (see below), whose sum is σ = 15732200052000. Its totient is φ = 10329644707456.

The previous prime is 13011032551087. The next prime is 13011032551159. The reversal of 13011032551135 is 53115523011031.

It is a cyclic number.

It is not a de Polignac number, because 13011032551135 - 211 = 13011032549087 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13011032551097 and 13011032551106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7047769 + ... + 8700178.

It is an arithmetic number, because the mean of its divisors is an integer number (983262503250).

Almost surely, 213011032551135 is an apocalyptic number.

13011032551135 is a deficient number, since it is larger than the sum of its proper divisors (2721167500865).

13011032551135 is a wasteful number, since it uses less digits than its factorization.

13011032551135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15749210.

The product of its (nonzero) digits is 6750, while the sum is 31.

Adding to 13011032551135 its reverse (53115523011031), we get a palindrome (66126555562166).

The spelling of 13011032551135 in words is "thirteen trillion, eleven billion, thirty-two million, five hundred fifty-one thousand, one hundred thirty-five".

Divisors: 1 5 149 745 1109 5545 165241 826205 15747947 78739735 2346444103 11732220515 17464473223 87322366115 2602206510227 13011032551135