Base | Representation |
---|---|
bin | 1011110101010101110111… |
… | …1110010010111011011111 |
3 | 1201001211202020012012021111 |
4 | 2331111131332102323133 |
5 | 3201133043313114020 |
6 | 43401104050242451 |
7 | 2512005341626453 |
oct | 275253576227337 |
9 | 51054666165244 |
10 | 13011032551135 |
11 | 4166a47750753 |
12 | 1561760586427 |
13 | 734c2056bc98 |
14 | 32da4736a663 |
15 | 1786a8005d5a |
hex | bd55df92edf |
13011032551135 has 16 divisors (see below), whose sum is σ = 15732200052000. Its totient is φ = 10329644707456.
The previous prime is 13011032551087. The next prime is 13011032551159. The reversal of 13011032551135 is 53115523011031.
It is a cyclic number.
It is not a de Polignac number, because 13011032551135 - 211 = 13011032549087 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13011032551097 and 13011032551106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7047769 + ... + 8700178.
It is an arithmetic number, because the mean of its divisors is an integer number (983262503250).
Almost surely, 213011032551135 is an apocalyptic number.
13011032551135 is a deficient number, since it is larger than the sum of its proper divisors (2721167500865).
13011032551135 is a wasteful number, since it uses less digits than its factorization.
13011032551135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15749210.
The product of its (nonzero) digits is 6750, while the sum is 31.
Adding to 13011032551135 its reverse (53115523011031), we get a palindrome (66126555562166).
The spelling of 13011032551135 in words is "thirteen trillion, eleven billion, thirty-two million, five hundred fifty-one thousand, one hundred thirty-five".
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