Base | Representation |
---|---|
bin | 11101100101010110101100… |
… | …001100010010011001111111 |
3 | 122001200102111211101120121121 |
4 | 131211112230030102121333 |
5 | 114023211430244344444 |
6 | 1140415510101211411 |
7 | 36256106230345465 |
oct | 3545265414223177 |
9 | 561612454346547 |
10 | 130110333199999 |
11 | 38503534138439 |
12 | 12714307400b67 |
13 | 577a475b05549 |
14 | 241b533718835 |
15 | 1009705a5c084 |
hex | 7655ac31267f |
130110333199999 has 2 divisors, whose sum is σ = 130110333200000. Its totient is φ = 130110333199998.
The previous prime is 130110333199963. The next prime is 130110333200017. The reversal of 130110333199999 is 999991333011031.
It is a strong prime.
It is an emirp because it is prime and its reverse (999991333011031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130110333199999 - 235 = 130075973461631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130110333191999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055166599999 + 65055166600000.
It is an arithmetic number, because the mean of its divisors is an integer number (65055166600000).
Almost surely, 2130110333199999 is an apocalyptic number.
130110333199999 is a deficient number, since it is larger than the sum of its proper divisors (1).
130110333199999 is an equidigital number, since it uses as much as digits as its factorization.
130110333199999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4782969, while the sum is 61.
The spelling of 130110333199999 in words is "one hundred thirty trillion, one hundred ten billion, three hundred thirty-three million, one hundred ninety-nine thousand, nine hundred ninety-nine".
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