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1301104213403 = 4397311940593
BaseRepresentation
bin10010111011101111110…
…110101011110110011011
311121101101012010022020212
4102323233312223312123
5132304130134312103
62433415150441335
7163000401223421
oct22735766536633
94541335108225
101301104213403
11461882455055
121901b520324b
1395902ac1b57
1446d8c0a3111
1523ca0d3e7d8
hex12eefdabd9b

1301104213403 has 8 divisors (see below), whose sum is σ = 1345087841328. Its totient is φ = 1257744466944.

The previous prime is 1301104213379. The next prime is 1301104213477. The reversal of 1301104213403 is 3043124011031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1301104213403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1301104213103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 155966126 + ... + 155974467.

It is an arithmetic number, because the mean of its divisors is an integer number (168135980166).

Almost surely, 21301104213403 is an apocalyptic number.

1301104213403 is a deficient number, since it is larger than the sum of its proper divisors (43983627925).

1301104213403 is an equidigital number, since it uses as much as digits as its factorization.

1301104213403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 311940733.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1301104213403 its reverse (3043124011031), we get a palindrome (4344228224434).

The spelling of 1301104213403 in words is "one trillion, three hundred one billion, one hundred four million, two hundred thirteen thousand, four hundred three".

Divisors: 1 43 97 4171 311940593 13413445499 30258237521 1301104213403