Search a number
-
+
1301109969941 is a prime number
BaseRepresentation
bin10010111011110000001…
…100101001010000010101
311121101101120221202201222
4102323300030221100111
5132304133123014231
62433415514100125
7163000501160345
oct22736014512025
94541346852658
101301109969941
11461885727021
121901b711a645
13959040590a2
1446d8cb60d25
1523ca15ca27b
hex12ef0329415

1301109969941 has 2 divisors, whose sum is σ = 1301109969942. Its totient is φ = 1301109969940.

The previous prime is 1301109969937. The next prime is 1301109969983. The reversal of 1301109969941 is 1499699011031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1084782657841 + 216327312100 = 1041529^2 + 465110^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301109969941 - 22 = 1301109969937 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301109969931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650554984970 + 650554984971.

It is an arithmetic number, because the mean of its divisors is an integer number (650554984971).

Almost surely, 21301109969941 is an apocalyptic number.

It is an amenable number.

1301109969941 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301109969941 is an equidigital number, since it uses as much as digits as its factorization.

1301109969941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 472392, while the sum is 53.

The spelling of 1301109969941 in words is "one trillion, three hundred one billion, one hundred nine million, nine hundred sixty-nine thousand, nine hundred forty-one".