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130111001233 is a prime number
BaseRepresentation
bin111100100101100111…
…0000101001010010001
3110102211122210200200121
41321023032011022101
54112431404014413
6135434442150241
712254162156053
oct1711316051221
9412748720617
10130111001233
11501a82a4a94
1221271ab2381
13c366b9a835
1464241218d3
1535b798cb8d
hex1e4b385291

130111001233 has 2 divisors, whose sum is σ = 130111001234. Its totient is φ = 130111001232.

The previous prime is 130111001197. The next prime is 130111001243. The reversal of 130111001233 is 332100111031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96653835664 + 33457165569 = 310892^2 + 182913^2 .

It is a cyclic number.

It is not a de Polignac number, because 130111001233 - 217 = 130110870161 is a prime.

It is not a weakly prime, because it can be changed into another prime (130111001243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055500616 + 65055500617.

It is an arithmetic number, because the mean of its divisors is an integer number (65055500617).

Almost surely, 2130111001233 is an apocalyptic number.

It is an amenable number.

130111001233 is a deficient number, since it is larger than the sum of its proper divisors (1).

130111001233 is an equidigital number, since it uses as much as digits as its factorization.

130111001233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 130111001233 its reverse (332100111031), we get a palindrome (462211112264).

The spelling of 130111001233 in words is "one hundred thirty billion, one hundred eleven million, one thousand, two hundred thirty-three".