13011110031 has 4 divisors (see below), whose sum is σ = 17348146712. Its totient is φ = 8674073352.

The previous prime is 13011110017. The next prime is 13011110033. The reversal of 13011110031 is 13001111031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13011110031 - 2⁵ = 13011109999 is a prime.

It is a super-2 number, since 2×13011110031² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13011109989 and 13011110016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011110033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2168518336 + ... + 2168518341.

It is an arithmetic number, because the mean of its divisors is an integer number (4337036678).

Almost surely, 2^13011110031 is an apocalyptic number.

13011110031 is a deficient number, since it is larger than the sum of its proper divisors (4337036681).

13011110031 is an equidigital number, since it uses as much as digits as its factorization.

13011110031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4337036680.

The product of its (nonzero) digits is 9, while the sum is 12.

Adding to 13011110031 its reverse (13001111031), we get a palindrome (26012221062).

The spelling of 13011110031 in words is "thirteen billion, eleven million, one hundred ten thousand, thirty-one".