Base | Representation |
---|---|
bin | 10010111011110000011… |
… | …000101000101100010001 |
3 | 11121101101210212110200221 |
4 | 102323300120220230101 |
5 | 132304134424111421 |
6 | 2433420105313041 |
7 | 163000536662005 |
oct | 22736030505421 |
9 | 4541353773627 |
10 | 1301113113361 |
11 | 461887483796 |
12 | 1901b8195781 |
13 | 959048b9ab9 |
14 | 46d8d33c705 |
15 | 23ca19eb841 |
hex | 12ef0628b11 |
1301113113361 has 2 divisors, whose sum is σ = 1301113113362. Its totient is φ = 1301113113360.
The previous prime is 1301113113299. The next prime is 1301113113367. The reversal of 1301113113361 is 1633113111031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 924799572225 + 376313541136 = 961665^2 + 613444^2 .
It is an emirp because it is prime and its reverse (1633113111031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1301113113361 - 211 = 1301113111313 is a prime.
It is not a weakly prime, because it can be changed into another prime (1301113113367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650556556680 + 650556556681.
It is an arithmetic number, because the mean of its divisors is an integer number (650556556681).
Almost surely, 21301113113361 is an apocalyptic number.
It is an amenable number.
1301113113361 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301113113361 is an equidigital number, since it uses as much as digits as its factorization.
1301113113361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 25.
Adding to 1301113113361 its reverse (1633113111031), we get a palindrome (2934226224392).
The spelling of 1301113113361 in words is "one trillion, three hundred one billion, one hundred thirteen million, one hundred thirteen thousand, three hundred sixty-one".
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