Search a number
-
+
130111320217 is a prime number
BaseRepresentation
bin111100100101100111…
…1010011000010011001
3110102211200101220020211
41321023033103002121
54112431444221332
6135434453051121
712254164655044
oct1711317230231
9412750356224
10130111320217
11501a84a270a
1221272026aa1
13c366c7ca98
1464241a5c5b
1535b7a02447
hex1e4b3d3099

130111320217 has 2 divisors, whose sum is σ = 130111320218. Its totient is φ = 130111320216.

The previous prime is 130111320169. The next prime is 130111320257. The reversal of 130111320217 is 712023111031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128515797081 + 1595523136 = 358491^2 + 39944^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130111320217 is a prime.

It is a super-2 number, since 2×1301113202172 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130111320257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055660108 + 65055660109.

It is an arithmetic number, because the mean of its divisors is an integer number (65055660109).

Almost surely, 2130111320217 is an apocalyptic number.

It is an amenable number.

130111320217 is a deficient number, since it is larger than the sum of its proper divisors (1).

130111320217 is an equidigital number, since it uses as much as digits as its factorization.

130111320217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 130111320217 its reverse (712023111031), we get a palindrome (842134431248).

The spelling of 130111320217 in words is "one hundred thirty billion, one hundred eleven million, three hundred twenty thousand, two hundred seventeen".