130111320257 has 2 divisors, whose sum is σ = 130111320258. Its totient is φ = 130111320256.

The previous prime is 130111320217. The next prime is 130111320259. The reversal of 130111320257 is 752023111031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116341705921 + 13769614336 = 341089^2 + 117344^2 .

It is a cyclic number.

It is not a de Polignac number, because 130111320257 - 2¹⁴ = 130111303873 is a prime.

Together with 130111320259, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130111320259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055660128 + 65055660129.

It is an arithmetic number, because the mean of its divisors is an integer number (65055660129).

Almost surely, 2^130111320257 is an apocalyptic number.

It is an amenable number.

130111320257 is a deficient number, since it is larger than the sum of its proper divisors (1).

130111320257 is an equidigital number, since it uses as much as digits as its factorization.

130111320257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1260, while the sum is 26.

Adding to 130111320257 its reverse (752023111031), we get a palindrome (882134431288).

The spelling of 130111320257 in words is "one hundred thirty billion, one hundred eleven million, three hundred twenty thousand, two hundred fifty-seven".