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130111411201 is a prime number
BaseRepresentation
bin111100100101100111…
…1101001010000000001
3110102211200120112001121
41321023033221100001
54112432010124301
6135434455032241
712254165514232
oct1711317512001
9412750515047
10130111411201
11501a8555002
122127206b681
13c366cb2315
1464241cb089
1535b7a1e3a1
hex1e4b3e9401

130111411201 has 2 divisors, whose sum is σ = 130111411202. Its totient is φ = 130111411200.

The previous prime is 130111411169. The next prime is 130111411219. The reversal of 130111411201 is 102114111031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77292340225 + 52819070976 = 278015^2 + 229824^2 .

It is a cyclic number.

It is not a de Polignac number, because 130111411201 - 25 = 130111411169 is a prime.

It is not a weakly prime, because it can be changed into another prime (130111411291) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65055705600 + 65055705601.

It is an arithmetic number, because the mean of its divisors is an integer number (65055705601).

Almost surely, 2130111411201 is an apocalyptic number.

It is an amenable number.

130111411201 is a deficient number, since it is larger than the sum of its proper divisors (1).

130111411201 is an equidigital number, since it uses as much as digits as its factorization.

130111411201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 130111411201 its reverse (102114111031), we get a palindrome (232225522232).

The spelling of 130111411201 in words is "one hundred thirty billion, one hundred eleven million, four hundred eleven thousand, two hundred one".