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13011200101 = 83156761447
BaseRepresentation
bin11000001111000011…
…10010100001100101
31020120202212110010001
430013201302201211
5203121331400401
65551031101301
7640300242664
oct140741624145
936522773101
1013011200101
115577535239
122631511831
1312c47c3893
148b6042ddb
15512415601
hex307872865

13011200101 has 4 divisors (see below), whose sum is σ = 13167961632. Its totient is φ = 12854438572.

The previous prime is 13011200071. The next prime is 13011200131. The reversal of 13011200101 is 10100211031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (13011200071) and next prime (13011200131).

It is a cyclic number.

It is not a de Polignac number, because 13011200101 - 29 = 13011199589 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011200131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78380641 + ... + 78380806.

It is an arithmetic number, because the mean of its divisors is an integer number (3291990408).

Almost surely, 213011200101 is an apocalyptic number.

It is an amenable number.

13011200101 is a deficient number, since it is larger than the sum of its proper divisors (156761531).

13011200101 is an equidigital number, since it uses as much as digits as its factorization.

13011200101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156761530.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 13011200101 its reverse (10100211031), we get a palindrome (23111411132).

The spelling of 13011200101 in words is "thirteen billion, eleven million, two hundred thousand, one hundred one".

Divisors: 1 83 156761447 13011200101