Base | Representation |
---|---|
bin | 1011110101010110100000… |
… | …0001010011010010100011 |
3 | 1201001212011222100221012222 |
4 | 2331111220001103102203 |
5 | 3201133414441024303 |
6 | 43401132511141255 |
7 | 2512012456440311 |
oct | 275255001232243 |
9 | 51055158327188 |
10 | 13011201111203 |
11 | 416702390a399 |
12 | 15617a8b1482b |
13 | 734c49468a79 |
14 | 32da618c70b1 |
15 | 1786b7bee938 |
hex | bd5680534a3 |
13011201111203 has 2 divisors, whose sum is σ = 13011201111204. Its totient is φ = 13011201111202.
The previous prime is 13011201111191. The next prime is 13011201111241. The reversal of 13011201111203 is 30211110211031.
It is a weak prime.
It is an emirp because it is prime and its reverse (30211110211031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13011201111203 is a prime.
It is not a weakly prime, because it can be changed into another prime (13011201111803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505600555601 + 6505600555602.
It is an arithmetic number, because the mean of its divisors is an integer number (6505600555602).
Almost surely, 213011201111203 is an apocalyptic number.
13011201111203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13011201111203 is an equidigital number, since it uses as much as digits as its factorization.
13011201111203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 13011201111203 its reverse (30211110211031), we get a palindrome (43222311322234).
The spelling of 13011201111203 in words is "thirteen trillion, eleven billion, two hundred one million, one hundred eleven thousand, two hundred three".
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