Base | Representation |
---|---|
bin | 10010111011110000111… |
… | …010100101101100111011 |
3 | 11121101102102121200002122 |
4 | 102323300322211230323 |
5 | 132304144213422021 |
6 | 2433421024151455 |
7 | 163001005432301 |
oct | 22736072455473 |
9 | 4541372550078 |
10 | 1301122014011 |
11 | 4618915029a6 |
12 | 1901bb16858b |
13 | 959066b5161 |
14 | 46d905b8271 |
15 | 23ca26a8bab |
hex | 12ef0ea5b3b |
1301122014011 has 2 divisors, whose sum is σ = 1301122014012. Its totient is φ = 1301122014010.
The previous prime is 1301122013977. The next prime is 1301122014041. The reversal of 1301122014011 is 1104102211031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1301122014011 is a prime.
It is not a weakly prime, because it can be changed into another prime (1301122014041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650561007005 + 650561007006.
It is an arithmetic number, because the mean of its divisors is an integer number (650561007006).
Almost surely, 21301122014011 is an apocalyptic number.
1301122014011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301122014011 is an equidigital number, since it uses as much as digits as its factorization.
1301122014011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1301122014011 its reverse (1104102211031), we get a palindrome (2405224225042).
The spelling of 1301122014011 in words is "one trillion, three hundred one billion, one hundred twenty-two million, fourteen thousand, eleven".
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