Base | Representation |
---|---|
bin | 11101100101011000011011… |
… | …101010001100111101101011 |
3 | 122001200121100011100011101012 |
4 | 131211120123222030331223 |
5 | 114023224243022004003 |
6 | 1140420415424214135 |
7 | 36256203456140132 |
oct | 3545303352147553 |
9 | 561617304304335 |
10 | 130112203313003 |
11 | 3850430382aa7a |
12 | 1271474976a34b |
13 | 577a6b33a36a2 |
14 | 241b66dc42919 |
15 | 10097b4d148d8 |
hex | 76561ba8cf6b |
130112203313003 has 2 divisors, whose sum is σ = 130112203313004. Its totient is φ = 130112203313002.
The previous prime is 130112203312999. The next prime is 130112203313033. The reversal of 130112203313003 is 300313302211031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130112203313003 - 22 = 130112203312999 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130112203313003.
It is not a weakly prime, because it can be changed into another prime (130112203313033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65056101656501 + 65056101656502.
It is an arithmetic number, because the mean of its divisors is an integer number (65056101656502).
Almost surely, 2130112203313003 is an apocalyptic number.
130112203313003 is a deficient number, since it is larger than the sum of its proper divisors (1).
130112203313003 is an equidigital number, since it uses as much as digits as its factorization.
130112203313003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 130112203313003 its reverse (300313302211031), we get a palindrome (430425505524034).
The spelling of 130112203313003 in words is "one hundred thirty trillion, one hundred twelve billion, two hundred three million, three hundred thirteen thousand, three".
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