130112233333 has 4 divisors (see below), whose sum is σ = 130119913440. Its totient is φ = 130104553228.

The previous prime is 130112233297. The next prime is 130112233409. The reversal of 130112233333 is 333332211031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130112233333 - 2¹⁷ = 130112102261 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130112233298 and 130112233307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130112236333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3814585 + ... + 3848542.

It is an arithmetic number, because the mean of its divisors is an integer number (32529978360).

Almost surely, 2^130112233333 is an apocalyptic number.

It is an amenable number.

130112233333 is a deficient number, since it is larger than the sum of its proper divisors (7680107).

130112233333 is an equidigital number, since it uses as much as digits as its factorization.

130112233333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7680106.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 130112233333 its reverse (333332211031), we get a palindrome (463444444364).

The spelling of 130112233333 in words is "one hundred thirty billion, one hundred twelve million, two hundred thirty-three thousand, three hundred thirty-three".