Base | Representation |
---|---|
bin | 10010111011110000111… |
… | …111001100101001100001 |
3 | 11121101102111220001022011 |
4 | 102323300333030221201 |
5 | 132304200021101423 |
6 | 2433421110112521 |
7 | 163001021623411 |
oct | 22736077145141 |
9 | 4541374801264 |
10 | 1301123222113 |
11 | 461892158630 |
12 | 1901bb64b741 |
13 | 95906a19000 |
14 | 46d90810641 |
15 | 23ca2846b0d |
hex | 12ef0fcca61 |
1301123222113 has 16 divisors (see below), whose sum is σ = 1537637270400. Its totient is φ = 1091851634640.
The previous prime is 1301123222099. The next prime is 1301123222137. The reversal of 1301123222113 is 3112223211031.
It is not a de Polignac number, because 1301123222113 - 213 = 1301123213921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1301123222713) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26895253 + ... + 26943586.
It is an arithmetic number, because the mean of its divisors is an integer number (96102329400).
Almost surely, 21301123222113 is an apocalyptic number.
1301123222113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1301123222113 is a deficient number, since it is larger than the sum of its proper divisors (236514048287).
1301123222113 is an equidigital number, since it uses as much as digits as its factorization.
1301123222113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53838889 (or 53838863 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1301123222113 its reverse (3112223211031), we get a palindrome (4413346433144).
The spelling of 1301123222113 in words is "one trillion, three hundred one billion, one hundred twenty-three million, two hundred twenty-two thousand, one hundred thirteen".
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