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130112520000 = 263542714001
BaseRepresentation
bin111100100101101001…
…1110111111101000000
3110102211202122212001020
41321023103313331000
54112432301120000
6135434534505440
712254211113001
oct1711323677500
9412752585036
10130112520000
11501a9142071
1221272505280
13c3672acc08
1464243d91a8
1535b7b8cba0
hex1e4b4f7f40

130112520000 has 280 divisors, whose sum is σ = 431877654912. Its totient is φ = 34560000000.

The previous prime is 130112519993. The next prime is 130112520061. The reversal of 130112520000 is 25211031.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 32518000 + ... + 32522000.

Almost surely, 2130112520000 is an apocalyptic number.

130112520000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130112520000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (215938827456).

130112520000 is an abundant number, since it is smaller than the sum of its proper divisors (301765134912).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130112520000 is an equidigital number, since it uses as much as digits as its factorization.

130112520000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4307 (or 4282 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

Adding to 130112520000 its reverse (25211031), we get a palindrome (130137731031).

It can be divided in two parts, 1301125 and 20000, that added together give a triangular number (1321125 = T1625).

The spelling of 130112520000 in words is "one hundred thirty billion, one hundred twelve million, five hundred twenty thousand".