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1301130013453 is a prime number
BaseRepresentation
bin10010111011110001011…
…001000110101100001101
311121101102222200002021021
4102323301121012230031
5132304203240412303
62433421511434141
7163001133430264
oct22736131065415
94541388602237
101301130013453
11461895a77006
12190201985951
139590825625a
1446d9169b5db
1523ca3238ebd
hex12ef1646b0d

1301130013453 has 2 divisors, whose sum is σ = 1301130013454. Its totient is φ = 1301130013452.

The previous prime is 1301130013411. The next prime is 1301130013459. The reversal of 1301130013453 is 3543100311031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1280115742084 + 21014271369 = 1131422^2 + 144963^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301130013453 - 225 = 1301096459021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301130013459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650565006726 + 650565006727.

It is an arithmetic number, because the mean of its divisors is an integer number (650565006727).

Almost surely, 21301130013453 is an apocalyptic number.

It is an amenable number.

1301130013453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301130013453 is an equidigital number, since it uses as much as digits as its factorization.

1301130013453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 1301130013453 its reverse (3543100311031), we get a palindrome (4844230324484).

The spelling of 1301130013453 in words is "one trillion, three hundred one billion, one hundred thirty million, thirteen thousand, four hundred fifty-three".