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130113012131 = 1091193697359
BaseRepresentation
bin111100100101101010…
…1110000000110100011
3110102211210120212010022
41321023111300012203
54112432412342011
6135434553224055
712254215232534
oct1711325600643
9412753525108
10130113012131
11501a9448893
122127270202b
13c367422c0b
1464244c668b
1535b7c388db
hex1e4b5701a3

130113012131 has 4 divisors (see below), whose sum is σ = 131306709600. Its totient is φ = 128919314664.

The previous prime is 130113012121. The next prime is 130113012143. The reversal of 130113012131 is 131210311031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130113012131 - 222 = 130108817827 is a prime.

It is a super-2 number, since 2×1301130121312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130113012121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596848571 + ... + 596848788.

It is an arithmetic number, because the mean of its divisors is an integer number (32826677400).

Almost surely, 2130113012131 is an apocalyptic number.

130113012131 is a deficient number, since it is larger than the sum of its proper divisors (1193697469).

130113012131 is a wasteful number, since it uses less digits than its factorization.

130113012131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1193697468.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 130113012131 its reverse (131210311031), we get a palindrome (261323323162).

The spelling of 130113012131 in words is "one hundred thirty billion, one hundred thirteen million, twelve thousand, one hundred thirty-one".

Divisors: 1 109 1193697359 130113012131