13011312121121 has 4 divisors (see below), whose sum is σ = 13110635114544. Its totient is φ = 12911989127700.

The previous prime is 13011312121081. The next prime is 13011312121139. The reversal of 13011312121121 is 12112121311031.

13011312121121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13011312121121 - 2¹⁰ = 13011312120097 is a prime.

It is a super-2 number, since 2×13011312121121² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13011312121093 and 13011312121102.

It is not an unprimeable number, because it can be changed into a prime (13011312121141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49661496515 + ... + 49661496776.

It is an arithmetic number, because the mean of its divisors is an integer number (3277658778636).

Almost surely, 2^{13011312121121} is an apocalyptic number.

It is an amenable number.

13011312121121 is a deficient number, since it is larger than the sum of its proper divisors (99322993423).

13011312121121 is an equidigital number, since it uses as much as digits as its factorization.

13011312121121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99322993422.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 13011312121121 its reverse (12112121311031), we get a palindrome (25123433432152).

The spelling of 13011312121121 in words is "thirteen trillion, eleven billion, three hundred twelve million, one hundred twenty-one thousand, one hundred twenty-one".