Base | Representation |
---|---|
bin | 111100100101101011… |
… | …0011110001111101001 |
3 | 110102211210221110101020 |
4 | 1321023112132033221 |
5 | 4112432434414004 |
6 | 135435001243053 |
7 | 12254216650542 |
oct | 1711326361751 |
9 | 412753843336 |
10 | 130113201129 |
11 | 501a956788a |
12 | 21272793489 |
13 | c36748ac52 |
14 | 64245354c9 |
15 | 35b7c748d9 |
hex | 1e4b59e3e9 |
130113201129 has 4 divisors (see below), whose sum is σ = 173484268176. Its totient is φ = 86742134084.
The previous prime is 130113201109. The next prime is 130113201131. The reversal of 130113201129 is 921102311031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 130113201129 - 212 = 130113197033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130113201099 and 130113201108.
It is not an unprimeable number, because it can be changed into a prime (130113201109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21685533519 + ... + 21685533524.
It is an arithmetic number, because the mean of its divisors is an integer number (43371067044).
Almost surely, 2130113201129 is an apocalyptic number.
It is an amenable number.
130113201129 is a deficient number, since it is larger than the sum of its proper divisors (43371067047).
130113201129 is an equidigital number, since it uses as much as digits as its factorization.
130113201129 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43371067046.
The product of its (nonzero) digits is 324, while the sum is 24.
The spelling of 130113201129 in words is "one hundred thirty billion, one hundred thirteen million, two hundred one thousand, one hundred twenty-nine".
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