Base | Representation |
---|---|
bin | 10010111011110001100… |
… | …001011111011111110101 |
3 | 11121101110010210210101211 |
4 | 102323301201133133311 |
5 | 132304204321242323 |
6 | 2433422030521421 |
7 | 163001161215541 |
oct | 22736141373765 |
9 | 4541403723354 |
10 | 1301132212213 |
11 | 461897238a69 |
12 | 190202666271 |
13 | 95908845cb2 |
14 | 46d91ab0a21 |
15 | 23ca352070d |
hex | 12ef185f7f5 |
1301132212213 has 2 divisors, whose sum is σ = 1301132212214. Its totient is φ = 1301132212212.
The previous prime is 1301132212207. The next prime is 1301132212229. The reversal of 1301132212213 is 3122122311031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1087385957284 + 213746254929 = 1042778^2 + 462327^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1301132212213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1301132212253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650566106106 + 650566106107.
It is an arithmetic number, because the mean of its divisors is an integer number (650566106107).
Almost surely, 21301132212213 is an apocalyptic number.
It is an amenable number.
1301132212213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301132212213 is an equidigital number, since it uses as much as digits as its factorization.
1301132212213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1301132212213 its reverse (3122122311031), we get a palindrome (4423254523244).
The spelling of 1301132212213 in words is "one trillion, three hundred one billion, one hundred thirty-two million, two hundred twelve thousand, two hundred thirteen".
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