130113300113 has 4 divisors (see below), whose sum is σ = 136961368560. Its totient is φ = 123265231668.

The previous prime is 130113300011. The next prime is 130113300127. The reversal of 130113300113 is 311003311031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311003311031 = 7 ⋅44429044433.

It is not a de Polignac number, because 130113300113 - 2¹² = 130113296017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130113300091 and 130113300100.

It is not an unprimeable number, because it can be changed into a prime (130113300193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3424034195 + ... + 3424034232.

It is an arithmetic number, because the mean of its divisors is an integer number (34240342140).

Almost surely, 2^130113300113 is an apocalyptic number.

It is an amenable number.

130113300113 is a deficient number, since it is larger than the sum of its proper divisors (6848068447).

130113300113 is an equidigital number, since it uses as much as digits as its factorization.

130113300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6848068446.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 130113300113 its reverse (311003311031), we get a palindrome (441116611144).

The spelling of 130113300113 in words is "one hundred thirty billion, one hundred thirteen million, three hundred thousand, one hundred thirteen".