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1301133104241 = 3433711034747
BaseRepresentation
bin10010111011110001100…
…100111001010001110001
311121101110012111010000220
4102323301210321101301
5132304210033313431
62433422102003253
7163001201622315
oct22736144712161
94541405433026
101301133104241
11461897798183
12190202a16529
1395908a99019
1446d91c63b45
1523ca3649b96
hex12ef1939471

1301133104241 has 4 divisors (see below), whose sum is σ = 1734844138992. Its totient is φ = 867422069492.

The previous prime is 1301133104237. The next prime is 1301133104267. The reversal of 1301133104241 is 1424013311031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301133104241 - 22 = 1301133104237 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1301133104291) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216855517371 + ... + 216855517376.

It is an arithmetic number, because the mean of its divisors is an integer number (433711034748).

Almost surely, 21301133104241 is an apocalyptic number.

It is an amenable number.

1301133104241 is a deficient number, since it is larger than the sum of its proper divisors (433711034751).

1301133104241 is an equidigital number, since it uses as much as digits as its factorization.

1301133104241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 433711034750.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 1301133104241 its reverse (1424013311031), we get a palindrome (2725146415272).

The spelling of 1301133104241 in words is "one trillion, three hundred one billion, one hundred thirty-three million, one hundred four thousand, two hundred forty-one".

Divisors: 1 3 433711034747 1301133104241