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13011341114 = 261106650337
BaseRepresentation
bin11000001111000100…
…10100111100111010
31020120210010121112202
430013202110330322
5203121400403424
65551034110202
7640301401052
oct140742247472
936523117482
1013011341114
115577621182
12263157b362
1312c4842b15
148b607c562
155124422ae
hex307894f3a

13011341114 has 8 divisors (see below), whose sum is σ = 19836962868. Its totient is φ = 6399020160.

The previous prime is 13011341099. The next prime is 13011341129. The reversal of 13011341114 is 41114311031.

13011341114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13011341099) and next prime (13011341129).

It can be written as a sum of positive squares in 2 ways, for example, as 12761543089 + 249798025 = 112967^2 + 15805^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53325047 + ... + 53325290.

Almost surely, 213011341114 is an apocalyptic number.

13011341114 is a deficient number, since it is larger than the sum of its proper divisors (6825621754).

13011341114 is a wasteful number, since it uses less digits than its factorization.

13011341114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 106650400.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13011341114 its reverse (41114311031), we get a palindrome (54125652145).

The spelling of 13011341114 in words is "thirteen billion, eleven million, three hundred forty-one thousand, one hundred fourteen".

Divisors: 1 2 61 122 106650337 213300674 6505670557 13011341114