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130113441401435 = 5123121139470577
BaseRepresentation
bin11101100101011001100101…
…011101001000101001011011
3122001200201112110000120102022
4131211121211131020221123
5114023234311444321220
61140421142332525055
736256246241542322
oct3545314535105133
9561621473016368
10130113441401435
1138504889691158
1212714a3432078b
13577a84ca425ab
14241b74a4490b9
151009838875925
hex765665748a5b

130113441401435 has 8 divisors (see below), whose sum is σ = 156262966512576. Its totient is φ = 104006195233920.

The previous prime is 130113441401417. The next prime is 130113441401467. The reversal of 130113441401435 is 534104144311031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130113441401435 - 224 = 130113424624219 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130113441401395 and 130113441401404.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10569729134 + ... + 10569741443.

It is an arithmetic number, because the mean of its divisors is an integer number (19532870814072).

Almost surely, 2130113441401435 is an apocalyptic number.

130113441401435 is a deficient number, since it is larger than the sum of its proper divisors (26149525111141).

130113441401435 is a wasteful number, since it uses less digits than its factorization.

130113441401435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21139471813.

The product of its (nonzero) digits is 34560, while the sum is 35.

Adding to 130113441401435 its reverse (534104144311031), we get a palindrome (664217585712466).

The spelling of 130113441401435 in words is "one hundred thirty trillion, one hundred thirteen billion, four hundred forty-one million, four hundred one thousand, four hundred thirty-five".

Divisors: 1 5 1231 6155 21139470577 105697352885 26022688280287 130113441401435