Base | Representation |
---|---|
bin | 11101100101011010011001… |
… | …001111010110101001001111 |
3 | 122001200210202222211022110110 |
4 | 131211122121033112221033 |
5 | 114023243101403011413 |
6 | 1140421404450211103 |
7 | 36256306621334340 |
oct | 3545323117265117 |
9 | 561623688738413 |
10 | 130114310203983 |
11 | 38505195045396 |
12 | 12715037283a93 |
13 | 577a95aa34c41 |
14 | 241b7cd9a40c7 |
15 | 1009889c8d8c3 |
hex | 7656993d6a4f |
130114310203983 has 8 divisors (see below), whose sum is σ = 198269425072768. Its totient is φ = 74351034402264.
The previous prime is 130114310203973. The next prime is 130114310204017. The reversal of 130114310203983 is 389302013411031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130114310203983 - 225 = 130114276649551 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130114310203963) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3097959766741 + ... + 3097959766782.
It is an arithmetic number, because the mean of its divisors is an integer number (24783678134096).
Almost surely, 2130114310203983 is an apocalyptic number.
130114310203983 is a deficient number, since it is larger than the sum of its proper divisors (68155114868785).
130114310203983 is an equidigital number, since it uses as much as digits as its factorization.
130114310203983 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6195919533533.
The product of its (nonzero) digits is 46656, while the sum is 39.
The spelling of 130114310203983 in words is "one hundred thirty trillion, one hundred fourteen billion, three hundred ten million, two hundred three thousand, nine hundred eighty-three".
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