Base | Representation |
---|---|
bin | 111100100101101110… |
… | …1111010001010100100 |
3 | 110102211221121111102011 |
4 | 1321023131322022210 |
5 | 4112433434304000 |
6 | 135435111124004 |
7 | 12254242350046 |
oct | 1711335721244 |
9 | 412757544364 |
10 | 130115150500 |
11 | 501aa679435 |
12 | 21273373604 |
13 | c3679c131a |
14 | 64248c1a96 |
15 | 35b800c2ba |
hex | 1e4b77a2a4 |
130115150500 has 24 divisors (see below), whose sum is σ = 284171489784. Its totient is φ = 52046060000.
The previous prime is 130115150497. The next prime is 130115150507. The reversal of 130115150500 is 5051511031.
It can be written as a sum of positive squares in 4 ways, for example, as 1396367424 + 128718783076 = 37368^2 + 358774^2 .
It is not an unprimeable number, because it can be changed into a prime (130115150507) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 130114651 + ... + 130115650.
It is an arithmetic number, because the mean of its divisors is an integer number (11840478741).
Almost surely, 2130115150500 is an apocalyptic number.
130115150500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130115150500 is an abundant number, since it is smaller than the sum of its proper divisors (154056339284).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130115150500 is a wasteful number, since it uses less digits than its factorization.
130115150500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 260230320 (or 260230308 counting only the distinct ones).
The product of its (nonzero) digits is 375, while the sum is 22.
Adding to 130115150500 its reverse (5051511031), we get a palindrome (135166661531).
The spelling of 130115150500 in words is "one hundred thirty billion, one hundred fifteen million, one hundred fifty thousand, five hundred".
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