Base | Representation |
---|---|
bin | 1011110101011001000011… |
… | …1110111100100000111011 |
3 | 1201001220221212112202121222 |
4 | 2331112100332330200323 |
5 | 3201141321410000413 |
6 | 43401325021222255 |
7 | 2512035503111516 |
oct | 275262076744073 |
9 | 51056855482558 |
10 | 13011888359483 |
11 | 416734683a182 |
12 | 156195b10198b |
13 | 735028961c60 |
14 | 32dac8ca1d7d |
15 | 178708203b08 |
hex | bd590fbc83b |
13011888359483 has 4 divisors (see below), whose sum is σ = 14012802848688. Its totient is φ = 12010973870280.
The previous prime is 13011888359443. The next prime is 13011888359573. The reversal of 13011888359483 is 38495388811031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13011888359483 - 216 = 13011888293947 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13011888359423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500457244583 + ... + 500457244608.
It is an arithmetic number, because the mean of its divisors is an integer number (3503200712172).
Almost surely, 213011888359483 is an apocalyptic number.
13011888359483 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13011888359483 is a deficient number, since it is larger than the sum of its proper divisors (1000914489205).
13011888359483 is a wasteful number, since it uses less digits than its factorization.
13011888359483 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1000914489204.
The product of its (nonzero) digits is 19906560, while the sum is 62.
The spelling of 13011888359483 in words is "thirteen trillion, eleven billion, eight hundred eighty-eight million, three hundred fifty-nine thousand, four hundred eighty-three".
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