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13012011041 is a prime number
BaseRepresentation
bin11000001111001001…
…11000100000100001
31020120211101122111212
430013210320200201
5203122033323131
65551100315505
7640310161151
oct140744704041
936524348455
1013012011041
115577a39537
122631842b95
1312c4a18a23
148b61b4761
15512525a2b
hex307938821

13012011041 has 2 divisors, whose sum is σ = 13012011042. Its totient is φ = 13012011040.

The previous prime is 13012010929. The next prime is 13012011121. The reversal of 13012011041 is 14011021031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7555086400 + 5456924641 = 86920^2 + 73871^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13012011041 is a prime.

It is a super-2 number, since 2×130120110412 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13012011541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506005520 + 6506005521.

It is an arithmetic number, because the mean of its divisors is an integer number (6506005521).

Almost surely, 213012011041 is an apocalyptic number.

It is an amenable number.

13012011041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13012011041 is an equidigital number, since it uses as much as digits as its factorization.

13012011041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 13012011041 its reverse (14011021031), we get a palindrome (27023032072).

The spelling of 13012011041 in words is "thirteen billion, twelve million, eleven thousand, forty-one".