Base | Representation |
---|---|
bin | 10010111011110101101… |
… | …000101101011100110000 |
3 | 11121101121221122102000010 |
4 | 102323311220231130300 |
5 | 132304330002310412 |
6 | 2433432533454520 |
7 | 163002656551644 |
oct | 22736550553460 |
9 | 4541557572003 |
10 | 1301201213232 |
11 | 4619221874a8 |
12 | 1902217a1440 |
13 | 95919c24bbb |
14 | 46d9ad12c24 |
15 | 23ca960033c |
hex | 12ef5a2d730 |
1301201213232 has 40 divisors (see below), whose sum is σ = 3365654178096. Its totient is φ = 433189517056.
The previous prime is 1301201213219. The next prime is 1301201213281. The reversal of 1301201213232 is 2323121021031.
It is a junction number, because it is equal to n+sod(n) for n = 1301201213199 and 1301201213208.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16968243 + ... + 17044754.
Almost surely, 21301201213232 is an apocalyptic number.
1301201213232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1301201213232 is an abundant number, since it is smaller than the sum of its proper divisors (2064452964864).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1301201213232 is a wasteful number, since it uses less digits than its factorization.
1301201213232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34013805 (or 34013799 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1301201213232 its reverse (2323121021031), we get a palindrome (3624322234263).
The spelling of 1301201213232 in words is "one trillion, three hundred one billion, two hundred one million, two hundred thirteen thousand, two hundred thirty-two".
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