13012022101320 has 768 divisors, whose sum is σ = 47709492480000. Its totient is φ = 3048733900800.

The previous prime is 13012022101313. The next prime is 13012022101363. The reversal of 13012022101320 is 2310122021031.

13012022101320 is a `hidden beast` number, since 1 + 3 + 0 + 120 + 221 + 0 + 1 + 320 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13012022101293 and 13012022101302.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 7448208687 + ... + 7448210433.

It is an arithmetic number, because the mean of its divisors is an integer number (62121735000).

Almost surely, 2^{13012022101320} is an apocalyptic number.

13012022101320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13012022101320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23854746240000).

13012022101320 is an abundant number, since it is smaller than the sum of its proper divisors (34697470378680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13012022101320 is a wasteful number, since it uses less digits than its factorization.

13012022101320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2354 (or 2347 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 13012022101320 its reverse (2310122021031), we get a palindrome (15322144122351).

The spelling of 13012022101320 in words is "thirteen trillion, twelve billion, twenty-two million, one hundred one thousand, three hundred twenty".