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1301210102113 = 3163166520633
BaseRepresentation
bin10010111011110110001…
…010100111100101100001
311121101122120101000020221
4102323312022213211201
5132304334241231423
62433433452203041
7163003125243025
oct22736612474541
94541576330227
101301210102113
114619271a8889
12190224769481
139591ba17aac
1446d9c188385
1523caa2a8e5d
hex12ef62a7961

1301210102113 has 8 divisors (see below), whose sum is σ = 1345313302016. Its totient is φ = 1257239944800.

The previous prime is 1301210102083. The next prime is 1301210102117. The reversal of 1301210102113 is 3112010121031.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1301210102113 - 213 = 1301210093921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1301210102117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33240756 + ... + 33279877.

It is an arithmetic number, because the mean of its divisors is an integer number (168164162752).

Almost surely, 21301210102113 is an apocalyptic number.

It is an amenable number.

1301210102113 is a deficient number, since it is larger than the sum of its proper divisors (44103199903).

1301210102113 is an equidigital number, since it uses as much as digits as its factorization.

1301210102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66521295.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 1301210102113 its reverse (3112010121031), we get a palindrome (4413220223144).

The spelling of 1301210102113 in words is "one trillion, three hundred one billion, two hundred ten million, one hundred two thousand, one hundred thirteen".

Divisors: 1 31 631 19561 66520633 2062139623 41974519423 1301210102113