1301211133331 has 4 divisors (see below), whose sum is σ = 1301221006752. Its totient is φ = 1301201259912.

The previous prime is 1301211133303. The next prime is 1301211133381. The reversal of 1301211133331 is 1333311121031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1301211133331 is a prime.

It is a super-2 number, since 2×1301211133331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301211133297 and 1301211133306.

It is not an unprimeable number, because it can be changed into a prime (1301211133381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4736315 + ... + 5003508.

It is an arithmetic number, because the mean of its divisors is an integer number (325305251688).

Almost surely, 2^{1301211133331} is an apocalyptic number.

1301211133331 is a deficient number, since it is larger than the sum of its proper divisors (9873421).

1301211133331 is an equidigital number, since it uses as much as digits as its factorization.

1301211133331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9873420.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1301211133331 its reverse (1333311121031), we get a palindrome (2634522254362).

The spelling of 1301211133331 in words is "one trillion, three hundred one billion, two hundred eleven million, one hundred thirty-three thousand, three hundred thirty-one".