Base | Representation |
---|---|
bin | 10010111011110110001… |
… | …110110110010101110001 |
3 | 11121101122122110100112022 |
4 | 102323312032312111301 |
5 | 132304340032223441 |
6 | 2433433532041225 |
7 | 163003140542213 |
oct | 22736616662561 |
9 | 4541578410468 |
10 | 1301211211121 |
11 | 461927896018 |
12 | 190225003215 |
13 | 9591c015803 |
14 | 46d9c3965b3 |
15 | 23caa42784b |
hex | 12ef63b6571 |
1301211211121 has 2 divisors, whose sum is σ = 1301211211122. Its totient is φ = 1301211211120.
The previous prime is 1301211211061. The next prime is 1301211211177. The reversal of 1301211211121 is 1211121121031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 824681934400 + 476529276721 = 908120^2 + 690311^2 .
It is a cyclic number.
It is not a de Polignac number, because 1301211211121 - 26 = 1301211211057 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1301211211121.
It is not a weakly prime, because it can be changed into another prime (1301211211021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650605605560 + 650605605561.
It is an arithmetic number, because the mean of its divisors is an integer number (650605605561).
Almost surely, 21301211211121 is an apocalyptic number.
It is an amenable number.
1301211211121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301211211121 is an equidigital number, since it uses as much as digits as its factorization.
1301211211121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 1301211211121 its reverse (1211121121031), we get a palindrome (2512332332152).
The spelling of 1301211211121 in words is "one trillion, three hundred one billion, two hundred eleven million, two hundred eleven thousand, one hundred twenty-one".
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