13012311113 has 4 divisors (see below), whose sum is σ = 13017834180. Its totient is φ = 13006788048.

The previous prime is 13012311079. The next prime is 13012311119. The reversal of 13012311113 is 31111321031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7682873104 + 5329438009 = 87652^2 + 73003^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13012311113 is a prime.

It is a super-3 number, since 3×13012311113³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13012311091 and 13012311100.

It is not an unprimeable number, because it can be changed into a prime (13012311119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2757998 + ... + 2762711.

It is an arithmetic number, because the mean of its divisors is an integer number (3254458545).

Almost surely, 2^13012311113 is an apocalyptic number.

It is an amenable number.

13012311113 is a deficient number, since it is larger than the sum of its proper divisors (5523067).

13012311113 is an equidigital number, since it uses as much as digits as its factorization.

13012311113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5523066.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13012311113 its reverse (31111321031), we get a palindrome (44123632144).

The spelling of 13012311113 in words is "thirteen billion, twelve million, three hundred eleven thousand, one hundred thirteen".