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130124310343 = 431301912553
BaseRepresentation
bin111100100110000000…
…0110110011101000111
3110102212120211212100121
41321030000312131013
54112443310412333
6135440035322411
712254413250116
oct1711400663507
9412776755317
10130124310343
1150204865355
1221276450407
13c36987a651
146425bc7c7d
1535b8c1b32d
hex1e4c036747

130124310343 has 4 divisors (see below), whose sum is σ = 130426223328. Its totient is φ = 129822397360.

The previous prime is 130124310341. The next prime is 130124310377. The reversal of 130124310343 is 343013421031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130124310343 - 21 = 130124310341 is a prime.

It is a super-2 number, since 2×1301243103432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130124310341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150955846 + ... + 150956707.

It is an arithmetic number, because the mean of its divisors is an integer number (32606555832).

Almost surely, 2130124310343 is an apocalyptic number.

130124310343 is a deficient number, since it is larger than the sum of its proper divisors (301912985).

130124310343 is an equidigital number, since it uses as much as digits as its factorization.

130124310343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 301912984.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 130124310343 its reverse (343013421031), we get a palindrome (473137731374).

The spelling of 130124310343 in words is "one hundred thirty billion, one hundred twenty-four million, three hundred ten thousand, three hundred forty-three".

Divisors: 1 431 301912553 130124310343