Base | Representation |
---|---|
bin | 10010111011111011100… |
… | …010101111010011000001 |
3 | 11121101212212010002220110 |
4 | 102323323202233103001 |
5 | 132310030334424413 |
6 | 2433450433501533 |
7 | 163005302066256 |
oct | 22737342572301 |
9 | 4541785102813 |
10 | 1301300311233 |
11 | 46197311227a |
12 | 19024aa118a9 |
13 | 95934610c80 |
14 | 46daa14b42d |
15 | 23cb31778c3 |
hex | 12efb8af4c1 |
1301300311233 has 32 divisors (see below), whose sum is σ = 1904266869120. Its totient is φ = 785493596160.
The previous prime is 1301300311163. The next prime is 1301300311309. The reversal of 1301300311233 is 3321130031031.
It is not a de Polignac number, because 1301300311233 - 213 = 1301300303041 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1301300311433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8379153 + ... + 8533041.
It is an arithmetic number, because the mean of its divisors is an integer number (59508339660).
Almost surely, 21301300311233 is an apocalyptic number.
1301300311233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1301300311233 is a deficient number, since it is larger than the sum of its proper divisors (602966557887).
1301300311233 is a wasteful number, since it uses less digits than its factorization.
1301300311233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 158049.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 1301300311233 its reverse (3321130031031), we get a palindrome (4622430342264).
The spelling of 1301300311233 in words is "one trillion, three hundred one billion, three hundred million, three hundred eleven thousand, two hundred thirty-three".
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