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1301310441401 is a prime number
BaseRepresentation
bin10010111011111100001…
…001011000011110111001
311121101220120011202212212
4102323330021120132321
5132310040433111101
62433451434544505
7163005454150265
oct22737411303671
94541816152785
101301310441401
11461978901213
12190252298135
1395936749b59
1446dab6270a5
1523cb3ec91bb
hex12efc2587b9

1301310441401 has 2 divisors, whose sum is σ = 1301310441402. Its totient is φ = 1301310441400.

The previous prime is 1301310441397. The next prime is 1301310441407. The reversal of 1301310441401 is 1041440131031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 881955765625 + 419354675776 = 939125^2 + 647576^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301310441401 - 22 = 1301310441397 is a prime.

It is not a weakly prime, because it can be changed into another prime (1301310441407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650655220700 + 650655220701.

It is an arithmetic number, because the mean of its divisors is an integer number (650655220701).

Almost surely, 21301310441401 is an apocalyptic number.

It is an amenable number.

1301310441401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301310441401 is an equidigital number, since it uses as much as digits as its factorization.

1301310441401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1301310441401 its reverse (1041440131031), we get a palindrome (2342750572432).

The spelling of 1301310441401 in words is "one trillion, three hundred one billion, three hundred ten million, four hundred forty-one thousand, four hundred one".