Base | Representation |
---|---|
bin | 10010111011111100001… |
… | …100010100001011100011 |
3 | 11121101220121121211111022 |
4 | 102323330030110023203 |
5 | 132310041132211321 |
6 | 2433451503240055 |
7 | 163005463531565 |
oct | 22737414241343 |
9 | 4541817554438 |
10 | 1301311210211 |
11 | 4619792868a1 |
12 | 1902525a902b |
13 | 95936958a7c |
14 | 46dab787335 |
15 | 23cb40cbdab |
hex | 12efc3142e3 |
1301311210211 has 4 divisors (see below), whose sum is σ = 1301530329000. Its totient is φ = 1301092091424.
The previous prime is 1301311210207. The next prime is 1301311210223. The reversal of 1301311210211 is 1120121131031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1301311210211 - 22 = 1301311210207 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1301311210211.
It is not an unprimeable number, because it can be changed into a prime (1301311210201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109550486 + ... + 109562363.
It is an arithmetic number, because the mean of its divisors is an integer number (325382582250).
Almost surely, 21301311210211 is an apocalyptic number.
1301311210211 is a deficient number, since it is larger than the sum of its proper divisors (219118789).
1301311210211 is an equidigital number, since it uses as much as digits as its factorization.
1301311210211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 219118788.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 1301311210211 its reverse (1120121131031), we get a palindrome (2421432341242).
The spelling of 1301311210211 in words is "one trillion, three hundred one billion, three hundred eleven million, two hundred ten thousand, two hundred eleven".
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