Base | Representation |
---|---|
bin | 10010111011111100001… |
… | …100110010001011110111 |
3 | 11121101220121212002002011 |
4 | 102323330030302023313 |
5 | 132310041200124421 |
6 | 2433451510025051 |
7 | 163005464553106 |
oct | 22737414621367 |
9 | 4541817762064 |
10 | 1301311333111 |
11 | 461979360169 |
12 | 190252648187 |
13 | 9593699c9aa |
14 | 46dab7ba03d |
15 | 23cb41034e1 |
hex | 12efc3322f7 |
1301311333111 has 2 divisors, whose sum is σ = 1301311333112. Its totient is φ = 1301311333110.
The previous prime is 1301311333079. The next prime is 1301311333121. The reversal of 1301311333111 is 1113331131031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1301311333111 - 25 = 1301311333079 is a prime.
It is a super-2 number, since 2×13013113331112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1301311333121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650655666555 + 650655666556.
It is an arithmetic number, because the mean of its divisors is an integer number (650655666556).
Almost surely, 21301311333111 is an apocalyptic number.
1301311333111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301311333111 is an equidigital number, since it uses as much as digits as its factorization.
1301311333111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 22.
Adding to 1301311333111 its reverse (1113331131031), we get a palindrome (2414642464142).
The spelling of 1301311333111 in words is "one trillion, three hundred one billion, three hundred eleven million, three hundred thirty-three thousand, one hundred eleven".
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