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1301312149 is a prime number
BaseRepresentation
bin100110110010000…
…0111001010010101
310100200122111200021
41031210013022111
510131113442044
6333043345141
744150653654
oct11544071225
93320574607
101301312149
11608614095
123039821b1
131797a72b7
14c4b8319b
157939de84
hex4d907295

1301312149 has 2 divisors, whose sum is σ = 1301312150. Its totient is φ = 1301312148.

The previous prime is 1301312081. The next prime is 1301312167. The reversal of 1301312149 is 9412131031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 715188049 + 586124100 = 26743^2 + 24210^2 .

It is an emirp because it is prime and its reverse (9412131031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1301312149 - 225 = 1267757717 is a prime.

It is a super-3 number, since 3×13013121493 (a number of 28 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301312449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650656074 + 650656075.

It is an arithmetic number, because the mean of its divisors is an integer number (650656075).

Almost surely, 21301312149 is an apocalyptic number.

It is an amenable number.

1301312149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301312149 is an equidigital number, since it uses as much as digits as its factorization.

1301312149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The square root of 1301312149 is about 36073.7043980792. The cubic root of 1301312149 is about 1091.7599570438.

The spelling of 1301312149 in words is "one billion, three hundred one million, three hundred twelve thousand, one hundred forty-nine".