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13013122220149 is a prime number
BaseRepresentation
bin1011110101011101101010…
…0001110000000001110101
31201002001010212021101021011
42331113122201300001311
53201201333242021044
643402051255152221
72512111204545112
oct275273241600165
951061125241234
1013013122220149
11416791a272a37
121562044375671
1373519448071c
1432dba4ac7909
1517877b6cc134
hexbd5da870075

13013122220149 has 2 divisors, whose sum is σ = 13013122220150. Its totient is φ = 13013122220148.

The previous prime is 13013122220143. The next prime is 13013122220213. The reversal of 13013122220149 is 94102222131031.

13013122220149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10869430921924 + 2143691298225 = 3296882^2 + 1464135^2 .

It is a cyclic number.

It is not a de Polignac number, because 13013122220149 - 29 = 13013122219637 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13013122220149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13013122220143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506561110074 + 6506561110075.

It is an arithmetic number, because the mean of its divisors is an integer number (6506561110075).

Almost surely, 213013122220149 is an apocalyptic number.

It is an amenable number.

13013122220149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13013122220149 is an equidigital number, since it uses as much as digits as its factorization.

13013122220149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 31.

The spelling of 13013122220149 in words is "thirteen trillion, thirteen billion, one hundred twenty-two million, two hundred twenty thousand, one hundred forty-nine".