Base | Representation |
---|---|
bin | 11000001111010010… |
… | …11101001110110001 |
3 | 1020120220122120012222 |
4 | 30013221131032301 |
5 | 203122340210113 |
6 | 5551142130425 |
7 | 640323313565 |
oct | 140751351661 |
9 | 36526576188 |
10 | 13013210033 |
11 | 557868833a |
12 | 2632120a15 |
13 | 12c50486a5 |
14 | 8b64076a5 |
15 | 5126b0e08 |
hex | 307a5d3b1 |
13013210033 has 2 divisors, whose sum is σ = 13013210034. Its totient is φ = 13013210032.
The previous prime is 13013210017. The next prime is 13013210057. The reversal of 13013210033 is 33001231031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10287639184 + 2725570849 = 101428^2 + 52207^2 .
It is a cyclic number.
It is not a de Polignac number, because 13013210033 - 24 = 13013210017 is a prime.
It is a super-2 number, since 2×130132100332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13013209993 and 13013210020.
It is not a weakly prime, because it can be changed into another prime (13013210003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6506605016 + 6506605017.
It is an arithmetic number, because the mean of its divisors is an integer number (6506605017).
Almost surely, 213013210033 is an apocalyptic number.
It is an amenable number.
13013210033 is a deficient number, since it is larger than the sum of its proper divisors (1).
13013210033 is an equidigital number, since it uses as much as digits as its factorization.
13013210033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 13013210033 its reverse (33001231031), we get a palindrome (46014441064).
The spelling of 13013210033 in words is "thirteen billion, thirteen million, two hundred ten thousand, thirty-three".
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