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1301321004169 is a prime number
BaseRepresentation
bin10010111011111100110…
…001101011010010001001
311121101221022001102021111
4102323330301223102021
5132310101134113134
62433452453210321
7163005643012444
oct22737461532211
94541838042244
101301321004169
1146198386617a
121902559309a1
13959389a7904
1446dacbb665b
1523cb4db3c64
hex12efcc6b489

1301321004169 has 2 divisors, whose sum is σ = 1301321004170. Its totient is φ = 1301321004168.

The previous prime is 1301321004161. The next prime is 1301321004229. The reversal of 1301321004169 is 9614001231031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 870466608144 + 430854396025 = 932988^2 + 656395^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301321004169 - 23 = 1301321004161 is a prime.

It is a super-2 number, since 2×13013210041692 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1301321004169.

It is not a weakly prime, because it can be changed into another prime (1301321004161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650660502084 + 650660502085.

It is an arithmetic number, because the mean of its divisors is an integer number (650660502085).

Almost surely, 21301321004169 is an apocalyptic number.

It is an amenable number.

1301321004169 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301321004169 is an equidigital number, since it uses as much as digits as its factorization.

1301321004169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 1301321004169 in words is "one trillion, three hundred one billion, three hundred twenty-one million, four thousand, one hundred sixty-nine".