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1301321004161 is a prime number
BaseRepresentation
bin10010111011111100110…
…001101011010010000001
311121101221022001102021012
4102323330301223102001
5132310101134113121
62433452453210305
7163005643012433
oct22737461532201
94541838042235
101301321004161
11461983866172
12190255930995
13959389a78c9
1446dacbb6653
1523cb4db3c5b
hex12efcc6b481

1301321004161 has 2 divisors, whose sum is σ = 1301321004162. Its totient is φ = 1301321004160.

The previous prime is 1301321004131. The next prime is 1301321004169. The reversal of 1301321004161 is 1614001231031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1300021834225 + 1299169936 = 1140185^2 + 36044^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301321004161 - 226 = 1301253895297 is a prime.

It is not a weakly prime, because it can be changed into another prime (1301321004169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650660502080 + 650660502081.

It is an arithmetic number, because the mean of its divisors is an integer number (650660502081).

Almost surely, 21301321004161 is an apocalyptic number.

It is an amenable number.

1301321004161 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301321004161 is an equidigital number, since it uses as much as digits as its factorization.

1301321004161 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1301321004161 its reverse (1614001231031), we get a palindrome (2915322235192).

The spelling of 1301321004161 in words is "one trillion, three hundred one billion, three hundred twenty-one million, four thousand, one hundred sixty-one".