Base | Representation |
---|---|
bin | 11101100101101011000000… |
… | …001101111000110000110011 |
3 | 122001202111210212021000112221 |
4 | 131211223000031320300303 |
5 | 114024041112331000201 |
6 | 1140433514234301511 |
7 | 36260510561161024 |
oct | 3545530015706063 |
9 | 561674725230487 |
10 | 130132144000051 |
11 | 38511806828326 |
12 | 12718593887897 |
13 | 577c5406b1cab |
14 | 241c6022c8c4b |
15 | 100a0807664a1 |
hex | 765ac0378c33 |
130132144000051 has 16 divisors (see below), whose sum is σ = 145039492546560. Its totient is φ = 116030681331840.
The previous prime is 130132144000049. The next prime is 130132144000093. The reversal of 130132144000051 is 150000441231031.
It is a cyclic number.
It is not a de Polignac number, because 130132144000051 - 21 = 130132144000049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130132144000021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 102121806 + ... + 103388236.
It is an arithmetic number, because the mean of its divisors is an integer number (9064968284160).
Almost surely, 2130132144000051 is an apocalyptic number.
130132144000051 is a deficient number, since it is larger than the sum of its proper divisors (14907348546509).
130132144000051 is a wasteful number, since it uses less digits than its factorization.
130132144000051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1584594.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 130132144000051 its reverse (150000441231031), we get a palindrome (280132585231082).
The spelling of 130132144000051 in words is "one hundred thirty trillion, one hundred thirty-two billion, one hundred forty-four million, fifty-one", and thus it is an aban number.
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